Understanding theoretical yield
Theoretical yield represents the best-case scenario: if every molecule of your limiting reagent reacted perfectly, no product was lost during workup, and no side reactions occurred, this is how much product you’d get. It’s the ceiling against which real experimental results are measured.
The calculation chain is: mass → moles (of reactant) → moles (of product, via stoichiometry) → mass (of product). Each step uses either molar mass or the balanced equation’s mole ratio.
Common mistakes: using the wrong mole ratio (check the balanced equation!), forgetting to identify the limiting reagent in multi-reactant problems, or confusing reactant and product molar masses.
How to Calculate Theoretical Yield (step by step)
Step One: Convert reactant mass to moles
moles of reactant = mass (g) ÷ molar mass of reactant (g/mol)
For 10 g with molar mass 40 g/mol: 10 ÷ 40 = 0.25 mol.
Step Two: Apply the mole ratio
moles of product = moles of reactant × (product coefficient ÷ reactant coefficient)
For a 1:1 ratio: 0.25 × 1 = 0.25 mol product.
Step Three: Convert product moles to grams
theoretical yield = moles of product × molar mass of product (g/mol)
For 0.25 mol with product molar mass 100 g/mol: 0.25 × 100 = 25.0 g.